Two electric charges of $9 μ C$ and $- 3 μ C$ are placed 0.16m apart in air. There are two points A and B on the line joining the two charges at distances of (i) $0.04 m$ from $- 3 μ C$ and in between the charges and (ii) $0.08 m$ from $- 3 μ C$ and out side the two charges. The potentials at A and B are :

0 V, 5 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0 V, 0 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 V, 0 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 V, 10 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0 V, 0 V$

V at $A = \frac{k (9 μ c)}{0.16 - 0.04} + \frac{k (- 3 μ c)}{0.04}$

$⟹ \frac{k (9 μ c)}{0.12} + \frac{k (- 3 μ c)}{0.04}$

$V_{A} = 0$

V at $B = \frac{k (9 μ c)}{0.24} + \frac{k (- 3 μ c)}{0.08}$

$⟹ \frac{k (9 μ c) + k (- 9 μ c)}{0.24}$

$V_{B} = 0$

Suggest Corrections

Similar questions

Two electric charges of $9 μ C$ and $- 3 μ C$ are placed $0.16 m$ apart in air. There will be a point P at which electric potential is $z e r o$ on the line joining the two charges and in between them. The distance of P from $9 μ C$ charge is:

Q. Two point charges

+ 3 μ C

and

- 3 μ C

are kept

20 c m

apart in air. Find the electric field midway between the charges on the line joining them. What will be the force experienced by a charge

+ 1.5 \times 10^{- 9} C

placed at this point ?

Q. Two point charges

q_{A} = 3 μ C

and

q_{B} = - 3 μ C

are located 20 cm apart in vacuum. What is the electric field at the midpoint O of the line AB joining the two charges?

Two point charges $q_{A} = 3 μ C$ and $q_{B} = - 3 μ C$ are located 20 cm apart in vacuum. What is the electric field at the midpoint O of the line AB joining the two charges?

If a negative test charge of magnitude $1.5 \times 10^{- 9} C$ is placed at this point, what is the force experienced by the test charge?

Two electric charges $12 μ C$ and $- 6 μ C$ are placed $20 c m$ apart in air. There will be a point P, at which electric potential is zero on the line joining these two charges and outside excluding the region between them. The distance of P from $- 6 μ C$ charge is:

Join BYJU'S Learning Program

Two electric charges of 9μC and −3μC are placed 0.16m apart in air. There are two points A and B on the line joining the two charges at distances of (i) 0.04m from −3μC and in between the charges and (ii) 0.08m from −3μC and out side the two charges. The potentials at A and B are :

The correct option is A 0V,0V V at A=k(9μc)0.16−0.04+k(−3μc)0.04 ⟹k(9μc)0.12+k(−3μc)0.04 VA=0 V at B=k(9μc)0.24+k(−3μc)0.08 ⟹k(9μc)+k(−9μc)0.24 VB=0