Question

Two electrical appliances are connected in parallel to a constant voltage supply. If the current in one appliance is $1\%$ less than that in the second appliance, then the power of the first appliance will be less by

• A. $5\%$
• B. $4\%$
• C. $2\%$
• D. $1\%$

Answer 1

Answer: (D)

$1\%$

Here, two electrical appliances are connected in parallel to a constant voltage supply hence, voltage is same for both the appliances. Also, power is
$P=\frac{V^2}{R}=VI$
$\Rightarrow P\propto I$
Hence, less current gives more resistance due to which the power will be less. Thus if the current in one appliance is $1\%$ less than that in the second appliance, then power of the first appliance will be also less $1\%$