Question

Two electrolytic cells containing molten solutions of nickel chloride and aluminium chloride are connected in series. If same amount of electric current is passed through them, what will be the weight of nickel obtained when 18 g of aluminium is obtained ?
[Al = 27 g/mol, Ni = 58.5 g/$mo{l}^{-1}$]

• A. 117 g
• B. 58.5 g
• C. 29.25 g
• D. 5.85 g

Answer 1

Answer: (B)

58.5 g

Since, w=Zit
or $\frac{(W{)}_{All}}{(W{)}_{All}}=\frac{(W{)}_{Ni}}{(W{)}_{Ni}}\Rightarrow \frac{\frac{18}{27}}{3}=\frac{\frac{(W{)}_{All}}{58.5}}{2}$
$\frac{18}{9}=\frac{2\times (W{)}_{Ni}}{58.5}$
$\Rightarrow (W{)}_{Ni}=58.5g$