Two electrons each of mass $9.1 \times 10^{- 31}$ kg are at a distance of $10 A^{0}$ . Calculate the gravitational force of attraction between them. Given $1 A^{0} = 10^{- 10} m .$

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Solution

$F = \frac{G M m}{d ²}$

$= \frac{G m ²}{d ²}$

$= G {(\frac{m}{d})}^{2}$

$= (6.67 \times 10^{- 11} N m^{2} / k g^{2}) \times {[\frac{(9.1 \times 10^{- 31} k g)}{(10 \times 10^{- 10} m)}]}^{2}$

$= 5.52 \times 10^{- 53} N e w t o n s$

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Two electrons each of mass 9.1×10−31 kg are at a distance of 10A0. Calculate the gravitational force of attraction between them. Given 1A0=10−10m.

F=GMmd² =Gm²d² =G(md)2 =(6.67×10−11Nm2/kg2)×[(9.1×10−31kg)(10×10−10m)]2 =5.52×10−53Newtons

Two electrons each of mass $9.1 \times 10^{- 31}$ kg are at a distance of $10 A^{0}$ . Calculate the gravitational force of attraction between them. Given $1 A^{0} = 10^{- 10} m .$

$F = \frac{G M m}{d ²}$

$= \frac{G m ²}{d ²}$

$= G {(\frac{m}{d})}^{2}$

$= (6.67 \times 10^{- 11} N m^{2} / k g^{2}) \times {[\frac{(9.1 \times 10^{- 31} k g)}{(10 \times 10^{- 10} m)}]}^{2}$

$= 5.52 \times 10^{- 53} N e w t o n s$