Two electrons- each of mass 9-1 x 10-31 kg- are at a distance 10 - Calculate the gravitational force of attraction between them- G - 6-67 x 10-11 Nm2 kg-2 - 1 - - 10-10 m

Given:The mass of each of the two electrons (m1) = 9.1 x 10 31 kg, (m2) = 9.1 x 10 31 kg.The distance between the two electrons (R) = 10 Å.Gravitational constan ...

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Standard XII

Physics

Centripetal Force

Two electrons...

Question

Two electrons, each of mass 9.1 x 10^-31kg, are at a distance 10 Å. Calculate the gravitational force of attraction between them. (G = 6.67 x 10^-11 Nm² kg^-2 ; 1 Å = 10^-10 m)

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Solution

Given:
The mass of each of the two electrons (m₁) = 9.1 x 10^-31kg, (m₂) = 9.1 x 10^-31kg.
The distance between the two electrons (R) = 10 Å.
Gravitational constant (G) = 6.67 x 10^-11 Nm² kg^-2.
1 Å = 10^-10 m.
Required to find:
The gravitational force (F) between the two electrons.
Solution:
The gravitational force of attraction (F) between two objects is given by $F = \frac{G m_{1} m_{2}}{R^{2}}$ .
By substituting the given values, we get
$F = \frac{(6.67 x 10^{- 11}) x (9.1 x 10^{- 31}) x (9.1 x 10^{- 31})}{{(10 x 10^{- 10})}^{2}} = \frac{552.34 x 10^{- 73}}{10^{- 18}} = 552.34 x 10^{- 55} = 5.52 x 10^{- 53}$
Therefore, the force of attraction between the two electrons is 5.52 x 10^-53 N.

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Two electrons, each of mass 9.1 x 10-31 kg, are at a distance 10 Å. Calculate the gravitational force of attraction between them. (G = 6.67 x 10-11 Nm2 kg-2 ; 1 Å = 10-10 m)

Two electrons, each of mass 9.1 x 10^-31kg, are at a distance 10 Å. Calculate the gravitational force of attraction between them. (G = 6.67 x 10^-11 Nm² kg^-2 ; 1 Å = 10^-10 m)