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Electronic Configuration

Two elements ...

Question

Two elements X and Y have the following electronic configurations $X = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2}$ and $Y = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$ . The formula of the compound formed by the combination of X and Y is :

A

X Y_{2}

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B

X_{5} Y_{2}

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C

X_{2} Y_{5}

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D

X Y_{5}

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Solution

The correct option is B $X Y_{2}$
X has a stable electronic configuration, with all the orbitals filled completely. For it to retain that stable configuration, it has to lose 2 electrons from its valence orbital 4s, thus, its valency is 2. While Y has one unpaired electron in 3p orbital which is highly reactive. So, 1 electron from Y contributes to the reaction, thus, valency of Y is 1.
$X^{2} Y^{1}$ $⟹$ $X Y_{2}$ .

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