Question

Two elements X (at mass 16) and Y (at mass 14) combine to form compounds A, B and C. The ratio of different masses of Y which combine with a fixed mass of X in A, B and C is 1 3 : 5. If 32 parts by mass of X combines with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with?

• A. 14 parts by mass of Y
• B. 42 parts by mass of Y
• C. 70 parts by mass of Y
• D. 84 parts by mass of Y

Answer 1

The correct option is C 70 parts by mass of Y

Mass ratio of Y in compound A , B and C is $1:3:5$, in compound B $32$ parts of X combine with $84$ parts of Y
$\therefore 16$ parts of X combine with $42$ parts of Y
For Y $3$ parts in compound B , then in compound C = $5$ parts
$\therefore 42$ parts in compound B, then in the compound C $=\frac{5}{3}\times 42=70$ parts