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Question
Two elements X (at mass 16) and Y (at mass 14) combine to form compounds A, B and C. The ratio of different masses of Y which combine with a fixed mass of X in A, B and C is 1 3 : 5. If 32 parts by mass of X combines with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with?
Two elements X (at mass 16) and Y (at mass 14) combine to form compounds A, B and C. The ratio of different masses of Y which combine with a fixed mass of X in A, B and C is 1 3 : 5. If 32 parts by mass of X combines with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with?
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Solution
The correct option is C 70 parts by mass of Y
Mass ratio of Y in compound A , B and C is 1:3:5, in compound B 32 parts of X combine with 84 parts of Y
∴16 parts of X combine with 42 parts of Y
For Y 3 parts in compound B , then in compound C = 5 parts
∴42 parts in compound B, then in the compound C =53×42=70 parts
Mass ratio of Y in compound A , B and C is 1:3:5, in compound B 32 parts of X combine with 84 parts of Y
∴16 parts of X combine with 42 parts of Y
For Y 3 parts in compound B , then in compound C = 5 parts
∴42 parts in compound B, then in the compound C =53×42=70 parts
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