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Question

Two engines pass each other moving in opposite directions with uniform speed of 30m/s. One of them is blowing a whistle of frequency 540Hz. Calculate the frequency heard by driver of second engine before they pass each other. Speed of sound is 330m/sec.

A
648Hz
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B
540Hz
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C
270Hz
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D
450Hz
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Solution

The correct option is A 648Hz
f=(c+vrcvs)fo
where
f: Observed frequency, fo: source frequency
c: speed of sound
vr: velocity of the receiver relative to the medium (positive if the receiver is moving towards the source)
vs: velocity of the source relative to the medium (positive if the source is moving away from the receiver)

f=(330+3033030)×540=648 Hz

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