Two equal and like charges when placed 5 cm apart experience a repulsive force of 0.144 newton. The magnitude of the charge in microcoloumb will be :

0.2

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Solution

The correct option is A 0.2
The force is given from Coulomb’s law as,

$F = \frac{1}{4 π ε_{0}} \times \frac{q_{1} q_{2}}{r^{2}}$

$0.144 = \frac{9 \times 10^{9} \times q \times q}{{(0.05)}^{2}}$

$q = 0.2 \times 10^{- 6} C$

$= 0.2 μ C$

Thus, the magnitude of the charge in micro coulomb is $0.2$ .

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Two equal and like charges when placed 5 cm apart experience a repulsive force of 0.144 newton. The magnitude of the charge in microcoloumb will be :

The correct option is A 0.2The force is given from Coulomb’s law as, F=14πε0×q1q2r2 0.144=9×109×q×q(0.05)2 q=0.2×10−6C =0.2μC Thus, the magnitude of the charge in micro coulomb is 0.2.