wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two equal and opposite charges of 4×108 C when placed 2×102 cm away, form a dipole. If this dipole is placed in an external electric field of 4×108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180 will be


A
64×104Nm and 64×104J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
32×104Nm and 32×104J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
64×104Nm and 32×104J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
32×104Nm and 64×104J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 32×104Nm and 64×104J

Dipole moment p=4×108×2×104=8×1012Cm
Maximum torque = pE=8×1012×4×108
=32×104Nm
Maximum work done in rotating through 180=2pE
=2×32×104=64×104J


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Torque and Potential Energy of a Dipole
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon