Two equal and opposite parallel forces, each of magnitude 40 N from a couple. If the magnitude of the torque is 100Nm. Find the perpendicular distance between their lines of action

2.5

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Solution

The correct option is A 2.5
$\to c = \to r \times \to f$
$100 N m = r \times 40 N$
$r = 2.5 m$

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Two equal and opposite parallel forces, each of magnitude 40 N from a couple. If the magnitude of the torque is 100Nm. Find the perpendicular distance between their lines of action

The correct option is A 2.5→c=→r×→f100 Nm=r×40 Nr=2.5 m

The correct option is A 2.5
$\to c = \to r \times \to f$
$100 N m = r \times 40 N$
$r = 2.5 m$