Two equal and opposite point charges are kept in a box. A vacuum is created in the box by evacuating the air inside the box. Then the electrostatic force between the two charges will:

Increase

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Decrease

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Be zero

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Be infinite

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Solution

The correct option is B Increase
The electrostatic force between two charge are given as

$F = \frac{Q q}{4 π ε_{0} r^{2}}$

The electrostatic force is inversely proportional to that of the dielectric permittivity.

The permittivity of free space (vacuum) is 1 and hence the electrostatic field in vacuum is more as there is no resistance to the field.

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