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Question

Two equal and positive charges are placed at a and a on x-axis, then graph of electric field along x-axis with distance x will be

A
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B
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C
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D
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Solution

The correct option is B
As we know that,
E = kQR2, where R is the distance from charge.
Here, electric field at any point between the charges is:
E = kQr2kQ(2ar)2
where r is the distance of point from one of the charges.

Now, beyond the point a and a, the field will be:
E = kQx2+kQ(2a+x)2
where x is the distance from the nearest charges.
Plotting these equations we get graph b.

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