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Question

# Two equal and positive charges are placed at a and −a on x-axis, then graph of electric field along x-axis with distance x will be

A
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B
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C
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D
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Solution

## The correct option is B As we know that, E = kQR2, where R is the distance from charge. Here, electric field at any point between the charges is: E = kQr2−kQ(2a−r)2 where r is the distance of point from one of the charges. Now, beyond the point a and −a, the field will be: E = kQx2+kQ(2a+x)2 where x is the distance from the nearest charges. Plotting these equations we get graph b.

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