Question

Two equal charges q of opposite sign are separated by a small distance '$2l$'. The electric potential at a point on the perpendicular bisector of the line joining the two charges at a distance r is :

• A. $\frac{1}{4\pi {\epsilon }_0}\frac{q}{r}$
• B. $\frac{1}{4\pi {\epsilon }_0}\frac{2q}{r}$
• C. Zero
• D. $\frac{1}{4\pi {\epsilon }_0}\frac{2q}{r^2}$

Answer 1

Answer: (C)

Zero

$V=\frac{Kq}{\sqrt{r^2+l^2}}+\frac{K(-q)}{\sqrt{r^2+l^2}}$

$\therefore V=0$