Question

Two equal chords, $AB$ and $CD$ are at a distance of 10 cm from each other. Find the distance of chord $AB$ from the centre.

Answer 1

Consider the figure:

$AB=CD$ [Given]

$EF=10cm$

We know that equal chords are equidistant from the centre.

So, $OE=OF$

$EF=OE+OF$

$\Rightarrow 2OE=10$

$\Rightarrow OE=OF=5cm$

So, both the chords, $AB$ and $CD$ are equidistant from the centre and is at a distance of 5 cm.