Two equal chords, AB and CD are at a distance of 10 cm from each other. Find the distance of chord AB from the centre.

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Solution

Consider the figure:

AB=CD [Given]
EF=10 cm
We know that equal chords are equidistant from the centre.
So, OE=OF
EF=OE+OF
$\Rightarrow 2 O E = 10$
$\Rightarrow O E = O F = 5 c m$
So, both the chords, AB and CD are equidistant from the centre and is at a distance of 5 cm.

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