Two equal chords, AB and CD are at a distance of 10 cm from each other. The distance of chord AB from the centre
Consider the figure:
AB=CD [Given]
EF=10 cm
We know that equal chords are equidistant from the centre.
So, OE=OF
EF=OE+OF
⇒2OE=10
⇒OE=OF=5 cm
So, both the chords, AB and CD are equidistant from the centre and is at a distance of 5 cm.