Question

Two equal chords AB and CD intersect at a point P inside the circle. If AP = 10 cm, PC = 5 cm, then the length of chord CD is

• A. 60°
• B. 50°
• C. 20°
• D. Can't be determined

Answer 1

The correct option is C

20°

Given AP = 10 cm

$\Rightarrow$ PD = 10 cm

Two equal chords intersect at a point inside or outside the circle, the corresponding parts of the chords are equal.

Given PC = 5 cm

$\Rightarrow$ CD = PC + PD

= 5 + 10 = 15 cm