Two equal forces are acting at a point with an angle of 60∘between them. If the resultat force is equal to 40√3N, the magnitude of each force is
A
40N
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B
20N
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C
80N
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D
30N
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Solution
The correct option is A40N Let |→R|=40√3N and angle between equal forces →P and →Q is 600. Also, according to question |→P|=|→Q| Thus, |→R|=√P2+Q2+2PQcosθ or, 40√3=√P2+P2+2P2×cos60∘ or, 40√3=P√3 or, |→P|=40N or, |→Q|=40N