Two equal masses are attached to the two ends of a spring of spring constant k. The masses are pulled symmetrically to stretch the spring by a length x over its natural length. The work done by the spring on each mass during the pulling is
A
12kx2
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B
−12kx2
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C
14kx2
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D
−14kx2
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Solution
The correct option is D−14kx2 work done by spring is =initial energy stored -final energy stored.
so work done by spring =0−12kx2
force applied by spring on both the blocks is same so work done by spring will be evenly distributed among both the blocks.