Two equal masses each of mass M are joined by a massless rod of length L Now an impulsive MV is given to the mass M making an angle of 30o with the length of the rod. The angular velocity of the rod just after imparting the impulse is :
The angle is given as,
sin30∘=rL/2
r=L4
The angular impulse about the center of mass is given as,
F=Mv×r
F=Mv×L4
The change in angular momentum is given as,
Iωf−Iωi=Mv×L4
2×ML2ω4−0=Mv×L4
ω=v2L
Thus, the angular velocity is v2L.