Two equal negative charges are fixed at the points [0,a] and [0,-a] on the y-axis. A positive charge Q is released from rest at the points [ 2a,0] on the x-axis. The charge Q will

move to the origin and stop there

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move to the origin, cross the origin and then move to infinitely.

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execute simple harmonic motion about the origin.

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execute oscillatory but not simple harmonic motion.

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Solution

The correct option is C move to the origin and stop there
The points $[0, a], [0, - a]$
$\Rightarrow d = \sqrt{{(0 + 0)}^{2} + {(a + a)}^{2}}$
$= \sqrt{{(2 a)}^{2}}$
$= \sqrt{{4 a}^{2}}$
$= 2 a$ (resting point $2 a$ )
The charge $= Q$
Move to the origin and stop there.

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Two equal negative charges are fixed at the points [0,a] and [0,-a] on the y-axis. A positive charge Q is released from rest at the points [ 2a,0] on the x-axis. The charge Q will

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Two equal negative charges are fixed at the points [0,a] and [0,a] on y-axis . A positive charge Q is released from rest at the points [2a,0] on the x-axis. The charge Q will

The correct option is C move to the origin and stop there
The points $[0, a], [0, - a]$
$\Rightarrow d = \sqrt{{(0 + 0)}^{2} + {(a + a)}^{2}}$
$= \sqrt{{(2 a)}^{2}}$
$= \sqrt{{4 a}^{2}}$
$= 2 a$ (resting point $2 a$ )
The charge $= Q$
Move to the origin and stop there.