CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two equal negative charges are fixed at the points [0,a] and [0,a] on y-axis . A positive charge Q is released from rest at the points [2a,0] on the x-axis. The charge Q will


A
move to infinity
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Move to origin and rest there
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Undergo SHM about the origin
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Execute oscillatory periodic motion but not SHM
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Execute oscillatory periodic motion but not SHM

The net force is given as,
Fn=2Fcosθ
Fn=2×14πE×q×Qa2+x2×xa2+x2

Thus, the restoring force is not linear, So, the motion will not be simple harmonic motion but the motion will be oscillatory.

1240346_1271655_ans_18c2118ea156417ebb3006a10018d981.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conductors, Insulators and Methods of Charging
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon