wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two equal point charges are fixed at x = -a and x = +a on the x-axis. Another point charge Q is placed at the origin. The Change in the electrical potential energy of Q, when it is displaced by a small distance x along the x-axis, is approximately proportional to

A
x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B x2
Initially according to figure (i) potential energy of Q is displaced by small distance x then it's potential energy now
Uf=kqQ[1(a+x)+1(ax)]=2kqQa(a2x2) .......... (i)

Hence change in potential energy
ΔU=UfUi=2kqQ[aa2x21a]=2kqQx2(a2x2)
Since x<<aΔu=2kqQx2a2ΔUx2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Idea of Charge
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon