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Question

# Two equal resistances when connected in series to a battery, consume electric power of 100 W. If these resistances are now connected in parallel combination to the same battery, the electric power consumed will be

A
400 W
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B
360 W
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C
240 W
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D
200 W
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Solution

## The correct option is A 400 WIn series connection with battery, Power, P=E22R Substituting the data given in the question, 100=E22R .......(1) In parallel combination with battery, Power , P′=E2(R2)=2E2R Substituting (1 in the above equation we get, P′=2×200=400 W Hence, option (a) is the correct answer.

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