Two equally charged pith balls 3 cm apart repel each other with a force of 4-10-5 N- The charge on each ball is

A square of side $\sqrt{2}$ has charges of $+ 2 \times 10^{- 9} C,$ $1 \times 10^{- 9} C, - 2 \times 10^{- 9} C a n d - 3 \times 10^{- 9} C$ respectively at its corners. The potential at the center of the square is

Q. Two equal charges placed in air and separated by a distance of

2 m

repel each other with a force of

10^{- 4} k g f

. Calculate the magnitude of either of the charges.

Q. The point-like charges carrying charges of

+ 3 \times 10^{- 9} C

and

- 5 \times 10^{- 9} C

are

2 m

apart. Determine the magnitude of the force between them and state whether it is attractive or repulsive.

Join BYJU'S Learning Program

Two equally charged pith balls 3 cm apart repel each other with a force of 4×10−5 N. The charge on each ball is

The correct option is D 2×10−9 CLet q be the charge on each particleF=q1q24πϵ0r2⟹4×10−5=q2×9×109(3×10−2)2On solving, q=2×10−9C

Two equally charged pith balls $3 c m$ apart repel each other with a force of $4 \times 10^{- 5} N$ . The charge on each ball is

The correct option is D $2 \times 10^{- 9} C$
Let $q$ be the charge on each particle
$F = \frac{q_{1} q_{2}}{4 π ϵ_{0} r^{2}}$
$⟹ 4 \times 10^{- 5} = \frac{q^{2} \times 9 \times 10^{9}}{(3 \times 10^{- 2})^{2}}$
On solving, $q = 2 \times 10^{- 9} C$