Question

Two equations of two S.H.M. are $y=asin(\omega t-\alpha )$ and $y=bcos(\omega t-\alpha )$. The phase difference between the two is

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

$y=asin(\omega t-\alpha )=acos⟮\omega t-\alpha -\frac{\pi }{2}⟯$

Another equation is given $y=cos(\omega t-\alpha )$

So, there exists a phase difference of $\frac{\pi }{2}={90}^{\circ }$