Two events A and B have probabilities 0.25 and 0.50 respectively. The probability that both A and B occur simultaneously is 0.12. Then the probability that neither A nor B occurs is:

0.13

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0.38

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0.63

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0.37

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Solution

The correct option is D 0.37
$P (A \cup B) = P (A) + P (B) - P (A \cap B) = 0.25 + 0.5 - 0.12 = 0.63 \Rightarrow P (¯ ¯¯¯¯¯¯¯¯¯¯¯¯ ¯ A \cup B) = 1 - 0.63 = 0.37$

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Two events A and B have probabilities 0.25 and 0.50 respectively. The probability that both A and B occur simultaneously is 0.12. Then the probability that neither A nor B occurs is:

The correct option is D 0.37P(A∪B)=P(A)+P(B)−P(A∩B)=0.25+0.5−0.12=0.63⇒P(¯¯¯¯¯¯¯¯¯¯¯¯¯¯A∪B)=1−0.63=0.37

The correct option is D 0.37
$P (A \cup B) = P (A) + P (B) - P (A \cap B) = 0.25 + 0.5 - 0.12 = 0.63 \Rightarrow P (¯ ¯¯¯¯¯¯¯¯¯¯¯¯ ¯ A \cup B) = 1 - 0.63 = 0.37$