Two events A and B have the probabilities 0.25 and 0.5 respectively. The probability that both A and B occur simultaneously is 0.14. Then the probability of neither A nor B occurs is equal to:
A
0.61
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B
0.39
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C
0.29
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D
0.19
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Solution
The correct option is B0.39 P(neither A nor B occurs) =P(¯A∩¯B) 1−P(A∪B) {By Demorgan law} =1−(P(A)+P(B)−P(A∩B)) =1−(0.25+0.5−0.14) =1−0.61=0.39