You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Spontaneity

Two exactly s...

Question

Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongation is 0.5 cm, then find elongation of copper wire. $[y_{s t} = 2 \times 10^{12} d y n e / c m^{- 2} & y_{c u} = 12 \times 10^{11} d y n e / c m^{2}]$

0.75 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.5 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.25 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.0 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1.25 cm
$Δ L_{s t} = \frac{σ L}{y_{s t}} a n d Δ L_{c u} = \frac{σ L}{y_{c u}}$
$Δ L_{c u} - Δ L_{s t} = 0.5 c m$

Suggest Corrections

Similar questions

Q. Two exactly similar wires of steel (y

=

20 x 10

^{11}

dyne/cm

^{2}

) and copper (y

=

12 x 10

^{11}

dyne/cm

^{2}

)are stretched by equal forces. If the total elongation is 1cm, elongation of copper wire is

A block of weight $100$ N is suspended by copper and steel wires of same cross sectional area $0.5 c m^{2}$ and length $\sqrt{3} m$ and $1 m$ respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are $30^{o}$ and $60^{o}$ respectively. If elongation in copper wire is $Δ l_{C}$ and elongation in steel wire is $Δ l_{S}$ , then the ratio $\frac{Δ l_{C}}{Δ l_{S}}$ is

(Young's modulus for copper and steel are $1 \times 10^{11} N / m^{2}$ and $2 \times 10^{11} N / m^{2}$ respectively)

Q. A copper wire and a steel wire of the same diameter and length 1 m and 2 m respectively are connected end and a force is applied which stretches their combined length by 1 cm. How much each wire is elongated respectively. Y of copper =

1.2 \times 10^{10}

M m^{- 2}

and Y of steel +

2.0 \times 10^{10} N m^{- 2}

Q. What force is required to stretch a copper wire

1 c m^{2}

in cross-section to double its length?

Y

for copper is

1.26 \times 10^{12} d y n e c m^{- 2}

Join BYJU'S Learning Program

Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongation is 0.5 cm, then find elongation of copper wire. [yst=2×1012dyne/cm−2&ycu=12×1011dyne/cm2]

The correct option is C 1.25 cmΔLst=σLyst and ΔLcu=σLycu ΔLcu−ΔLst=0.5cm

Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongation is 0.5 cm, then find elongation of copper wire. $[y_{s t} = 2 \times 10^{12} d y n e / c m^{- 2} & y_{c u} = 12 \times 10^{11} d y n e / c m^{2}]$

The correct option is C 1.25 cm
$Δ L_{s t} = \frac{σ L}{y_{s t}} a n d Δ L_{c u} = \frac{σ L}{y_{c u}}$
$Δ L_{c u} - Δ L_{s t} = 0.5 c m$