The correct option is D √u2+v22
From third equation of motion v2–u2=2as
From the given question, we can infer that the initial velocity of the train was u and final velocity is v.
Therefore acceleration of the train if length of train is l is a = v2–u22l
When the middle part of the train passes the pole, the trains has displaced by l/2, then
let V be the velocity of the middle then using the third equation of motion we get,
V2=u2+2al2
Now, substituting value of a here we get,
V = √u2+v22
Therefore, option D is correct.