Two fair coins are tossed. Find the probability of obtaining 2 Heads

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\frac{2}{3}

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\frac{1}{2}

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\frac{1}{4}

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Solution

The correct option is D $\frac{1}{4}$
$W h e n t w o c o i n s a r e t o s s e d t h e n f o u r o u t c o m e s a r e$

$H H, H T, T H, T T$

$P = \frac{1}{4}$

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