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Standard XII

Mathematics

Event

Two fair dice...

Question

Two fair dice are rolled. Let A_i represents the event that the sum of the faces of the dice is
divisible by i. Then answer the following
Then which one of the following events are most probable

A_{6}

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A_{5}

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A_{4}

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A_{3}

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Solution

The correct option is D $A_{3}$
$P (A_{3}) = \frac{12}{36}, P (A_{4}) = \frac{9}{36}, P (A_{5}) = \frac{7}{36} a n d P (A_{6}) = \frac{6}{36}$
$∴ A_{3}$ is most probable

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Two fair dice are rolled. Let Ai represents the event that the sum of the faces of the dice is divisible by i. Then answer the following Then which one of the following events are most probable

The correct option is D A3P(A3)=1236,P(A4)=936,P(A5)=736 and P(A6)=636 ∴A3 is most probable

Two fair dice are rolled. Let A_i represents the event that the sum of the faces of the dice is
divisible by i. Then answer the following
Then which one of the following events are most probable

The correct option is D $A_{3}$
$P (A_{3}) = \frac{12}{36}, P (A_{4}) = \frac{9}{36}, P (A_{5}) = \frac{7}{36} a n d P (A_{6}) = \frac{6}{36}$
$∴ A_{3}$ is most probable