The correct option is A 211
Let A be the event of getting four on at least one of the dice and B be the event of showing 6 on other dice.
Then we have to find P(BA)
P(BA)=P(B∩A)P(A)=P(B∩A)P(A)A=(1,4),(4,1),(4,2),(2,4),(3,4),(4,3),(4,4),(4,5),(5,4),(6,4),(4,6)
and A∩B={(4,6),(6,4)}.
∴P(BA)=211