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Question

Two fair dice are rolled simultaneously. If one of the dice shows four, then the probability of other die showing six, is equal to:

A
211
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B
118
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C
16
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D
136
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Solution

The correct option is A 211
Let A be the event of getting four on at least one of the dice and B be the event of showing 6 on other dice.
Then we have to find P(BA)
P(BA)=P(BA)P(A)=P(BA)P(A)A=(1,4),(4,1),(4,2),(2,4),(3,4),(4,3),(4,4),(4,5),(5,4),(6,4),(4,6)
and AB={(4,6),(6,4)}.
P(BA)=211

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