Question

Two fair dice are rolled. The probability of the sum of digits on their faces to be greater than or equal to $10$ is

• A. $\frac{1}{5}$
• B. $\frac{1}{4}$
• C. $\frac{1}{8}$
• D. $\frac{1}{6}$

Answer 1

The correct option is D $\frac{1}{6}$

We have, $E=\left\{\right(5,5),(6,4),(4,6),(6,5),(5,6),(6,6\left)\right\}$

$\Rightarrow n\left(E\right)=6$

and $n\left(S\right)=\frac{1}{6\cdot 6}=\frac{1}{36}$

$\therefore P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{1}{6}$