Two fair dice are thrown together. The probability that the number $5$ does not appear on any of them is

\frac{1}{36}

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\frac{5}{36}

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\frac{11}{36}

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\frac{25}{36}

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Solution

The correct option is D $\frac{25}{36}$
$T w o d i c e s a r e t h r o w n f o r 5 n o t t o p e a p p e a r e d o n a n y o n e, o n l y 5 o u t o f 6 a r e f a v o u r a b l e o u t c o m e s T h e r e f o r e p r o b a b i l i t y = \frac{f a v o u r a b l e o u t c o m}{T o t a l o u t c o n m e} = \frac{5}{6} * \frac{5}{6} = \frac{25}{36}$

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Similar questions

Q. Two dice are thrown simultaneously. The probability of obtaining total score of seven is
(a) 5/36
(b) 6/36
(c) 7/36
(d) 8/36

Q. Two dice are thrown together and the number appearing on them noted. X denotes the sum of the two numbers. Assuming that all the 36 outcomes are equally likely, what is the probability distribution of X?

Q. (i) Complete the following table:

Event: 'Sum on $2$ dice'	$2$	$3$	$4$	$5$	$6$	$7$	$8$	$9$	$10$	$11$	$12$
Probability	$\frac{1}{36}$						$\frac{5}{36}$				$\frac{1}{36}$

(ii) A student argues that there are

11

possible outcomes

2, 3, 4, 5, 6, 7, 8, 9, 10, 11

and

12

. Therefore, each of them has a probability

\frac{1}{11}

. Do you agree with this argument?
Justify your answer.

Two dice, one blue and one grey, are thrown at the same time.

(i) Write down all the possible outcomes and complete the following table:

Event:

Sum of two dice

Probability

(ii) A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability. Do you agree with this argument?

Two dice are rolled simultaneously. Find the probability that number appearing on the first die is of the form of 5p or 2p and the number appearing on the second die is of the form 3q. (where 'p' and‘q’ can take values 1, 2 or 3).

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Two fair dice are thrown together. The probability that the number 5 does not appear on any of them is

The correct option is D 2536Twodicesarethrownfor5nottopeappearedonanyone,only5outof6arefavourableoutcomesThereforeprobability=favourableoutcomTotaloutconme=56∗56=2536

Two fair dice are thrown together. The probability that the number $5$ does not appear on any of them is