Question

Two fair dice are tossed simultaneously. Find the probability that the product of the numbers that land showing is at least $25$.

• A. $\frac{1}{36}$
• B. $\frac{1}{12}$
• C. $\frac{1}{9}$
• D. $\frac{1}{4}$
• E. $\frac{3}{2}$

Answer 1

The correct option is C $\frac{1}{9}$

Two dice are thrown simultaneously, total number of possible outcomes is $6\times 6=36$.
The product of numbers on two dice will be atleast $25$ for four possible set of outcomes ( they are $(5,5),(5,6),(6,5),(6,6)$.
Therefore probability is $\frac{4}{36}=\frac{1}{9}$.