Question

Two fair die are thrown, find the probability that sum of the points on their uppermost faces is a perfect square or divisible by $4$:

• A. $\frac{12}{36}$
• B. $\frac{13}{36}$
• C. $\frac{15}{36}$
• D. $\frac{16}{36}$

Answer 1

Answer: (B)

$\frac{13}{36}$

two fair dice thrown
so total cases$=6\times 6=36$
and perfect square or divisible by $4$ that mean that sum should be equal to $=4,8,9,12$
for getting $4=(1,3);(2,2);(3,1)$
for getting $8=(2,6);(3,5);(4,4);(5,3);(6,2)$
for getting $9=(3,6);(4,5);(5,4);(6,3)$
for getting $12=(6,6)$
so total cases$=3+5+4+1=13$
so probability =$\frac{13}{36}$