Two faraday of electricity is passed through a solution of $C u S O_{4}$ . The mass of copper deposited at the cathode is : (at mass of $C u = 63.5 u)$ .

127 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

63.5 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $63.5 g$
Equivalent mass of copper $= \frac{A t o m i c m a s s}{V a l e n c y}$
$= \frac{63.5}{2} = 31.75$
Amount of copper deposited by $2 f a r a d a y = 2 \times 31.75$
$= 63.5 g$ .

Suggest Corrections

Similar questions

C u S O_{4}

C u S O_{4}

C u

2 F a r a d a y

C u S O_{4}

Join BYJU'S Learning Program