Two finite sets have m and n elements. The total number of subsets of the first set is 56 more than the total number of subsets of the second set. Find the values of m and n.
No. of subsets of Set A of m elements = 2m
Again No. of subsets of Set B of n elements = 2n
Set A have 56 more subsets than Set B.
It means 2m−2n = 56
Then it is clear m > n.
Let m = n + k,
Now 2m−2n = 56
or 2n+k - 2n = 56
or 2n(2k−1) =56
or 2n(2k−1) = 8×7 =23(23−1)
Thus we see n=3, k=3
m = n+k= 3+3 = 6
Ans. n= 3, m = 6