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Question

Two fixed point charges +16μC and 9μC are placed 8cm apart in air. Where should a third point charge placed so that, the third charge is in equilibrium


A
0.24m from the charge +16μc and within the system of charge
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B
0.24m from the charge +16μc and outside the system along the straight line joining the two charges
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C
0.24m from the charge 9μc and within the system of charges
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D
0.24m from the 9μc and outside the system along the straight lint joining the two charges.
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Solution

Step 1: Given the data and diagram used

0.24m from the charge +16μc and within the system of charge

Step 2: Calculation of distance of where third point charge placed so that, the third charge is in equilibrium

Fq=K(9)×θ(0.08+x)2,F+16q=K×15μC(x)2

|Fq|=|F+16q|9(0.8+x2)=16x2
(x0.8+x)2=(169)x0.8+x=43

[(16)/(x+0.08)2]=(9/x2)

[x/(x+0.08)]2=(9/16)[x/(x+0.8)]

=(3/4)4x=3x+0.24x=0.24m=24cm

24 cm from −9μC outside their joining line

x=0.24m

The correct option is A

896548_967897_ans_13ebb6f6b72d4e81b535ed6be7b1a51b.png


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