Two fixed point charges +16μC and −9μC are placed 8cm apart in air. Where should a third point charge placed so that, the third charge is in equilibrium
Step 1: Given the data and diagram used
0.24m from the charge +16μc and within the system of charge
Step 2: Calculation of distance of where third point charge placed so that, the third charge is in equilibrium
F−q=K(−9)×θ(0.08+x)2,F+16q=K×15μC(x)2
∴[(16)/(x+0.08)2]=(9/x2)
∴[x/(x+0.08)]2=(9/16)[x/(x+0.8)]
=(3/4)4x=3x+0.24x=0.24m=24cm
24 cm from −9μC outside their joining line
x=0.24m
The correct option is A