Question

Two flask $A$ and $B$ of equal volumes maintained temperature 300 K and 700 K contain equal mass of $He\left(g\right)$ and $N_2\left(g\right)$ respectively. What is the ratio of total translation kinetic energy of gas in flask $A$ to that of flask $B$?

• A. $1:3$
• B. $3:1$
• C. $3:49$
• D. None of these

Answer 1

Answer: (B)

$3:1$

$K.E=\frac{1}{2}m{v}^2$

$v=\sqrt{\frac{3RT}{M}}$ , Its Given Masses of $H_2$ and $N_2$ are Equal .

Ratio of K.E would become $\frac{T_1}{M_1}:\frac{T_2}{M_2}$

Ratio of Total translation kinetic energy of Flask A to that of flask B = $\frac{300}{4}:\frac{700}{28}$ = $3:1$