Two flasks I and II shown below are connected by a valve of negligible volume-When the valve is openend- the final pressure of the system in bar is x - 10-2- The value of x is -Integer answer-Assume - ideal gas- 1 bar -105 Pa-Molar mass of N2-28-0 g mol-1 R-8-31 J mol-1 K-1

Number of moles of flask I=2.828=0.1 Number of moles of flask II=0.228=1140 Assuming the system attains a final temperature of T Heat lost by N_2 of flask I = H ...

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Byju's Answer

Standard XII

Chemistry

System, Surroundings, Intensive, Extensive Properties

Two flasks I ...

Question

Two flasks $I$ and $I I$ shown below are connected by a valve of negligible volume.

When the valve is openend, the final pressure of the system in bar is $x \times 10^{- 2}$ . The value of $x$ is _____.
(Integer answer)
[Assume - ideal gas: $1 b a r = 10^{5} P a .$
Molar mass of $N_{2} = 28.0 g m o l^{- 1}$ $R = 8.31 J m o l^{- 1} K^{- 1}$

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Solution

Number of moles of flask $I = \frac{2.8}{28} = 0.1$
Number of moles of flask $I I = \frac{0.2}{28} = \frac{1}{140}$
Assuming the system attains a final temperature of T
Heat lost by $N_{2}$ of flask I = Heat gained by $N_{2}$ of flask II
$n_{I} C_{m} (300 - T) = n_{I I} C_{m} (T - 60)$
$0.1 (300 - T) = \frac{1}{140} (T - 60)$
$Final temperature T = 284 K$
$P_{T} = \frac{n_{1} R T}{V_{1}} = \frac{(\frac{1}{10} + \frac{1}{140}) m o l \times 8.31 J m o l^{- 1} K^{- 1} \times 284 K}{3 \times 10^{- 3} m^{3}} \times 10^{- 5} \frac{b a r}{P a} = 84.2$
$P_{T} = 84.28 \times 10^{- 2} b a r x = 84 (nearest integer)$

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Two flasks I and II shown below are connected by a valve of negligible volume. When the valve is openend, the final pressure of the system in bar is x×10−2. The value of x is _____. (Integer answer) [Assume - ideal gas: 1 bar=105 Pa. Molar mass of N2=28.0 g mol−1 R=8.31 J mol−1 K−1