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Stoichiometric Calculations

Two flasks of...

Question

Two flasks of equal volume are connected by a narrow tube (of negligible volume) all at $27^{o} C$ and contain $0.70 m o l$ of $H_{2}$ at $0.5 a t m$ . One of the flask is then immersed into a bath kept at $127^{o} C$ , while the other remains at $27^{o} C$ . The final pressure in each flask is:

Final pressure in the apparatus is

0.5714 a t m

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Number of moles in one of the flasks are

0.4

and in other are

0.3

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Final pressure is

3.7281 a t m

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Both

(a)

and

(b)

are correct

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Solution

The correct option is A Final pressure in the apparatus is $0.5714 a t m$
We know, $P V = n R T$

$0.5 V = 0.7 R 300$

so $V = 420 R$

In the 2nd case, the pressure will be the same in both flasks and the sum of moles of gas will be 0.7. But Volume will be half $420 R / 2 = 210 R$

Flask 1-
$P V = a R T$
$P 210 R = a R 300 \Rightarrow a = 0.7 P$

Flask2-
$P V = b R T$
$P 210 R = b R 400 \Rightarrow b = 0.525 P$

$a + b = 1.225 P = 0.7$

$P = 0.571 a t m$

Hence, the correct option is $A$

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Two flasks of equal volume are connected by a narrow tube (of negligible volume) all at 27oC and contain 0.70 mol of H2 at 0.5 atm. One of the flask is then immersed into a bath kept at 127oC, while the other remains at 27oC. The final pressure in each flask is:

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