Two force are acting on the block of mass 2 kg as shown in the figure. The force of friction due to horizontal surface on the block is 4 N. Then the acceleration of the block is:

{1 m / s}^{2}

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{2 m / s}^{2}

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{3 m / s}^{2}

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{4 m / s}^{2}

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Solution

The correct option is C ${3 m / s}^{2}$
Net Force on Block $= (14 - (4 +$ Friction Force $) N$

$= (14 - (4 + 4)] N$
$= 6 N$

$N e t A c c e l e r a t i o n = \frac{N e t F o r c e}{M a s s o f B l o c k}$

$= \frac{6 N}{2 K g}$
$= 3 m / s^{2}$

Correct Answer is ©

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