Question

two forces act on a block having equal magnitude two forces act such that defective resultant force also has the same magnitude what is the angle between the two forces

Answer 1

Dear student
$$\begin{gathered} F_1=F_2=F_{resul\tan t} \\ letanglebetweenthetwoforcesis\theta \\ {F^2}_{resul\tan t}={F^2}_1+{F^2}_2+2F_1{F}_2\cos \theta \\ {F}^2=F^2+F^2+2F\times F\cos \theta \\ {F}^2=2F^2+2F^2\cos \theta \\ {F}^2=2F^2+2F^2\cos \theta \\ 1=2+2\cos \theta \\ \cos \theta =\frac{-1}{2} \\ \theta =120°=\frac{2\pi }{3} \\ Regards \end{gathered}$$