Two forces each equal to $F / 2$ act at right angle. Then-effect may be neutralized by a third force acting along their bisector in the opposite direction. What is the magnitude of that third force?

Open in App

Solution

Magnitude of third force required to magnitude of resultant of these two forces.
$\Rightarrow | F | = \sqrt{{(\frac{F}{2})}^{2} + {(\frac{F}{2})}^{2}} = \frac{F}{2} \sqrt{2} = \frac{F}{\sqrt{2}}$ .

Suggest Corrections

Similar questions

Q. Two equal forces

\to F

each act at right angles to each other.The third force which can neutralize their effect is:

A body is acted upon by two forces each of magnitude F, but in opposite directions. State the effect of forces if the forces act along same line of action.

Q. The resultant of two forces acting in opposite direction is

10 N

. If these forces act perpendicular to each other their resultant will be

50 N

the magnitude of these forces will be:-

Q. Two forces each of magnitude

10

N act simultaneously on a body with their directions inclined to each other at an angle of

120^{0}

and displaces the body over

10

m along the bisector of the angle between the two forces. Then the work done by each force is:

Q. Parallelogram law of forces states that if two forces acting simultaneously at a point be represented in magnitude and direction by two adjacent sides of a parallelogram, their resultant may be represented in magnitude and direction by

Join BYJU'S Learning Program

Two forces each equal to F/2 act at right angle. Then-effect may be neutralized by a third force acting along their bisector in the opposite direction. What is the magnitude of that third force?

Magnitude of third force required to magnitude of resultant of these two forces.⇒|F|=√(F2)2+(F2)2=F2√2=F√2.

Two forces each equal to $F / 2$ act at right angle. Then-effect may be neutralized by a third force acting along their bisector in the opposite direction. What is the magnitude of that third force?

Magnitude of third force required to magnitude of resultant of these two forces.
$\Rightarrow | F | = \sqrt{{(\frac{F}{2})}^{2} + {(\frac{F}{2})}^{2}} = \frac{F}{2} \sqrt{2} = \frac{F}{\sqrt{2}}$ .