Question

Two forces, $F_1=20N$ and $F_2=30N$ are acting on an object.
(a) What is the net force acting on the object?
(b) What is the direction of the net force acting due to the application of these two forces?
(c) Name the force.

Answer 1

Step 1: Given

Given: $F_1=20Nand{F}_2=30N$

Step 2: Finding the net force and the direction of the net force acting due to the application of these two forces and the force's name.

(a): When all of the forces are pulling in the same direction
Net force, $F=F_2+F_1=30+20=50N$

Therefore, the net force will be 50N.

(b): The direction of the net force acts along the direction of $F_{1}or{F}_2$

1. When the forces are in opposition to one another.
2. Net force, $F=F_2-F_1=30-20=10N$

Hence, the direction of the net force acts along the direction of $F_{2}as{F}_2$ is greater in magnitude.

(c): Here the net force is non-zero. Hence the force name is unbalanced force.